2 Feb 2013

SOAL ULANGAN HARIAN



USAHA DAN ENERGI

1.       Seseorang yang massanya 50 kg menaiki tangga yang tingginya 20 meter. Jika g = 10 m/s2, berapakah usaha yang dilakukan oleh orang tersebut!
2.       Sebuah benda ditarik dengan gaya tetap sebesar 40 N, membentuk sudut 600 terhadap lintasan. Jika benda berpindah sejauh 10 meter dan lantai kasar dengan kekasaran 0,3.berapakah besar usaha yang dilakukan oleh benda
3.       Sebuah benda yang massanya 2 kg jatuh bebas dari ketinggian 10 meter di tempat yang mempunyai percepatan grafitasi 10 m/s2. Hitunglah:
a)       Energi potensial benda pada ketinggian tersebut
b)       Energi mekanik pada ketinggian tersebut
c)       Kecepatan benda pada ketinggian tersebut
d)       Energi potensial benda pada ketinggian  2 meter diatas tanah
e)       Energi kinetik benda pada ketinggian 2 meter diatas tanah
f)        Kecepatan benda sesaat menyentuh tanah
4.       Sebuah mesin derek digunakan untuk mengangkat sebuah benda yang massanya 2 ton sampai mecapai ketinggian 5 meter dalam waktu 10 detik.                       Jika g = 10 m/s2 berapakah daya angkat derek tersebut?
di

25 komentar:

  1. Ratih SulastriSel Mar 19, 11:24:00 AM 2013

    1. dik:
    m= 50 kg
    h= 20 m
    g=10 m/s2
    dit:w?
    jawab w=m.g.h
    =50.10.20
    =10000 joule

    2.
    dik: f=40N
    s=10 m
    sudut 60 derajat dgn kekasaran 0,3
    dit w?
    jawab
    w=f.s.cos 60
    = -40.10.1/2
    = -200 joule (karena mengalami pergesekan sehingga usahanya negatif)

    3.
    dik: m= 2 kg
    h= 1o m
    g= 10 m/s2
    dit a.Ep? b.Em? c. V? d. Ep h= 2m e. Ek? f. V?

    jawab
    a.Ep= m.g.h
    = 2.10.10
    =200 joule
    b.Em= m.g.h + 1/2 m.v2
    = 2.10.10 + 1/2 2.200
    = 200 + 200
    = 400 joule
    c.vt2-v02= 2. a.s
    vt2-0 = 2.10.10
    = 200 m/s
    d. Ep= m.g.h
    = 2.10.2
    = 40 joule
    e. Ek= 1/2 m.v2
    =1/2.2.40 2
    = 1600 joule
    f.vt2= vo2+2.a.s
    = 0 + 2.10.2
    =40 m/s
    4.dik
    m= 2 ton= 2000 kg
    h= 5 m
    t= 10 sekon
    g= 10 m/s2
    dit p?
    jawab P=w/t
    = m.g.h/t
    = 2000.5.10/10
    = 100000/10
    = 10000 watt

    BalasHapus
  2. Salma SaidahSel Mar 19, 11:43:00 AM 2013

    1. Dik:m=50 kg
    h=20 m
    g=10 m/s
    Dit: W?
    Jawab : W=m.g.h
    =50.10.20
    =10000 Joule

    2. Dik: F=40N
    s=10m
    sudut= 60
    Dit: W?
    Jawab : W =ΣF. s
    =F.Sin 60.s
    =40 1/2√3. 10
    =200√3 Joule

    3. Dik:m=2kg
    h=10m
    g=10m/s2
    Dit: a)E.Pot?
    b)E.m?
    c)Vo?
    d)E.Pot dengan h=2m
    e)E.Kin dengan h=2m
    f)Vt?
    Jawab : a) E.pot=m.g.h
    =2.10.10
    =200 Joule

    b)E.m=m.g.h + 1/2.m.v2
    =2.10.10+1/2.2.0
    =200+0
    =200 Joule

    c) Ema = Emb
    Epa+Eka = Epb+Ekb
    mgha + 0 = 0+ 1/2mv2
    mgha = 1/2 mvb2
    1/2vb2 = gha
    vb2 = gha/1/2
    vb = √2.10.10
    vb = 10 √2 m/s

    d)E.pot=m.g.h
    =2.10.2
    =40 Joule

    e)E.kin=1/2.m.v2
    =1/2.2.v2
    =0 Joule

    f)Vt2=Vo2+2gh
    Vt2=0 + 2.10.10
    Vt2=200
    Vt=√200

    4. Dik:m=2ton=2000kg
    h=5m
    t=10 sekon
    g=10m/s2
    Dit:P?
    Jawab : P=W/t
    =m.g.h/t
    =2000.10.5/10
    =100000/10
    =10000 Watt

    BalasHapus
  3. Sera SeptianiSel Mar 19, 11:45:00 AM 2013

    1. Dik :m=50 kg
    h=20 m
    g=10 m/s2
    Dit :w ?
    Jawab :
    w=m.g.h
    =50kg.10m/s2.20m
    =10000 J

    2. Dik :f=40 N
    sin 60(derajat)=1/2 akar 3
    s=10 m
    Dit :w?
    Jawab :
    w=sigma F.s
    =sin 60 derajat.40 N.10 m
    =1/2 akar 3.400 N/m
    =200 akar 3

    3. Dik :m=2 kg
    h=10 m
    g=10 m/s2
    Dit :Epot ?
    Jawab :
    a.Epot=m.g.h
    =2 kg.10 m/s2.10 m
    =200 J
    b.EmA=EpA + EkA
    =200 J + 1/2.m.v2
    =200 J + 1/2.2.02
    =200 J
    c.Ema = Emb
    Epa+Eka = Epb+Ekb
    mgha + 0= 0+ 1/2mv2
    mgha = 1/2 mvb2
    1/2vb2 = gha
    vb2 = gha/1/2
    vb = akar 2.10.10
    vb = 10 akar 2 m/s
    d.Epot=m.g.(h2-h1)
    =2kg.10m/s2.(10-2)
    =20.8
    =160 J
    e.Ekin=1/2.m.v2
    =1/2.2.02
    =0
    f.Vt2=Vo2 + 2.g.h
    Vt2=0 + 2.10 m/s2.10m
    Vt2=200
    Vt =akar dari 200
    =10 akar 2 m/s

    4. Dik :m=2 ton=2000kg
    h=5 m
    g=10 m/s2
    t=10 s
    Dit :P?
    Jawab :
    P=W/t
    =m.g.h/t
    =2000kg.10 m/s2.5m/10 s
    =100000/10
    =10000 watt

    BalasHapus
  4. irsyan sugiar riyansyahSel Mar 19, 11:46:00 AM 2013

    1. Dik : m= 50kg h=20m g=10m/s2
    dit : w
    jwb : W = m.g.h
    w=50.10.20=10.000 joule
    2.dik: F : 40 N sudut = 60 s = 10
    jwb : W =ΣF. s
    =F.cos 60.s
    =40 .1/2. 10
    =200Joule
    3. Dik : m=2kg, h=10m, g=1om/s
    jwb :
    A). ep=m.g.h= 2.10.10 =200 joule
    B). em= m.g.h+ 1/2 m.v2
    = 2.10.10+1/2 2.02
    =200+1.0
    =200
    c) Ema = Emb
    Epa+Eka = Epb+Ekb
    mgha + 0= 0+ 1/2mv2
    mgha = 1/2 mvb2
    1/2vb2= gha
    vb2= gha/1/2
    vb= akar 2.10.10
    vb= 10 akar 2 m/s
    D). ketinggian 2m diatas tanah
    ep=m.g.h=2.2.10=40 joule
    E).ketinggian 2m diatas tanah
    ek=1/2 m.v2 = 1/2 2.02=0
    F) Vt2=Vo2+2gh
    Vt2=0 + 2.10.10
    Vt2=200
    Vt=√200
    4.dik : m=2 ton=2000kg, h=5m, t=10s,g=10
    dit: daya
    jwb : P: W/t= m.g.h/t= 2000.10.5/10= 10.000 joule

    BalasHapus
  5. AnonimSel Mar 19, 11:46:00 AM 2013

    1.
    dik :
    m : 50kg
    h : 20 m
    g : 10m/s2

    dit :
    w ??

    penyelesain :
    w :
    mgh
    50.10.20
    10.000 joule

    2.dik:
    F : 40 N
    sudut = 60
    s = 10
    penyelesaian :
    W =ΣF. s
    =F.cos 60.s
    =40 .1/2. 10
    =200Joule

    4.
    dik :
    m : 2ton-> 2.000 kg
    h : 5 m
    t : 10 s
    g : 10m/s2

    dit : p ??

    penyelesaian :

    p : w/t
    mgh/t
    2.000.10.5/10
    2.000.5
    10.000watt

    3.
    dik :
    m : 2 kg
    h : 10 m
    g : 10m/s2

    dit :
    a.Ep ?
    b.Em
    c.v ?
    d.Ep ? h:2m diatas tanah
    e.Ek? h: 2m diatas tanah
    f.v pd saat menyentuh tanah ?

    penyelesaian:
    a.
    Ep : mgh
    2.10.10
    200 joule

    b.
    em: m.g.h+ 1/2 m.v2
    :2.10.10+1/2 2.02
    :200+1.0
    =200joule

    c.
    Ema = Emb
    Epa+Eka = Epb+Ekb
    mgha + 0= 0+ 1/2mv2
    mgha = 1/2 mvb2
    1/2vb2= gha
    vb2= gha/1/2
    vb= akar 2.10.10
    vb= 10 akar 2 m/s

    d.
    ep:m.g.h
    :2.2.10
    :40 joule

    e.
    ek:1/2 m.v2
    : 1/2 2.02
    :0

    f.
    Vt2:Vo2+2gh
    Vt2:0 + 2.10.10
    Vt2:200
    Vt:√200
    vt : akar 200


    BalasHapus
  6. AnonimSel Mar 19, 11:48:00 AM 2013

    1.Dik : m= 50kg h=20m g=10m/s2
    dit : w
    jwb : W = m.g.h
    w=50.10.20=10.000 joule

    2. Dik: F : 40 N sudut = 60 s = 10
    Jwb : W =ΣF. s
    =F.cos 60.s
    =40 .1/2. 10
    =200Joule

    3. Dik : m = 2kg
    h = 10
    g = 10m/s2
    Dit : a. Ep
    b. Em
    c. v
    d. Ep pada ketinggian 2m diatas tanah
    e. Ek pada ketinggian 2m diatas tanah
    f. v pada saat menyentuh tanah
    Jwb :
    a. Ep= mgh
    = 2.10.10
    = 200 joule
    b. Em=m.g.h +m.v2 = 2.10.10 + 1/2 2.02 =200+1.0
    = 200
    c. Ema = Emb Epa+Eka
    = Epb+Ekb
    mgha + 0
    = 0+ 1/2mv2
    mgha
    = 1/2 mvb2
    1/2vb2= gha
    vb2= gha/1/2
    vb= akar 2.10.10
    vb= 10 akar 2 m/s
    d. ketinggian 2m diatas tanah
    ep
    =m.g.h=2.2.10=40 joule
    e. ketinggian 2m diatas tanah
    ek
    =1/2 m.v2 = 1/2 2.02=0
    f. Vt2=Vo2+2gh
    Vt2=0 + 2.10.10
    Vt2=200
    Vt=√200


    4. Dik : m = 2 ton -> 2000kg
    h = 5m
    t = 10 s
    g= 10m/s2
    Dit : p
    jwb : w/t
    mgh/t
    2000.10.5/10
    10.000 watt

    BalasHapus
  7. intan haiza nulfitriSel Mar 19, 11:50:00 AM 2013

    1.Dik : m = 50kg, h=20m, & g=10
    Dit : w ?
    jawab : ep = m.g.h
    = 50.10.20 = 10000 joule

    2.dik: F =40 N
    sudut = 60
    s = 10
    jawab
    W =ΣF. s
    =F.cos 60.s
    =40 .1/2. 10
    =200Joule
    3. a). ep=mgh=2.10.10=200 joule
    b). em=m.g.h + 1/2.m.v2 = 2.10.10 + 1/2 2.0,2 =200+1.0 = 200
    c) Ema = Emb
    Epa+Eka = Epb+Ekb
    mgha + 0= 0+ 1/2mv2
    mgha = 1/2 mvb2
    1/2vb2= gha
    vb2= gha/1/2
    vb= akar 2.10.10
    vb= 10 akar 2 m/s
    d). s=10-2= 8 m
    ep= mgh = 2.10.8 = 160 joule
    e). ek=1/2.m.v2 = 1/2 2.0,2= 0
    f). f) Vt2=Vo2+2gh
    Vt2=0 + 2.10.10
    Vt2=200
    Vt=√200

    4. P=W/T F=W/S = 2/5 =0.4
    =(F.S)/T
    =(0,4 X 5)/10
    =2/10
    =0,2 watt

    BalasHapus
  8. AnonimSel Mar 19, 11:52:00 AM 2013

    1. dik : m=50kg
    h=20meter
    g=10m/s2
    dit : w?
    jawab: w=m.g.h
    50.20.10
    10.ooo joule

    2. dik : F : 40 N sudut = 60 s = 10
    dit : w?
    jwb : W =ΣF. s
    =F.cos 60.s
    =40 .1/2. 10
    =200Joule

    3. dik : m=2kg h=10m g=10m/s
    jwb :
    a. ep=m.g.h =2.10.10 =200 joule
    b. em=m.g.h +m.v2 = 2.10.10 + 1/2 2.02
    =200+1.0 = 200
    c. Ema = Emb
    Epa+Eka = Epb+Ekb
    mgha + 0= 0+ 1/2mv2
    mgha = 1/2 mvb2
    1/2vb2= gha
    vb2= gha/1/2
    vb= akar 2.10.10
    vb= 10 akar 2 m/s
    d. ketinggian 2m diatas tanah
    ep
    =m.g.h=2.2.10=40 joule
    e. ketinggian 2m diatas tanah
    ek=1/2 m.v2 = 1/2 2.02=0
    f. Vt2=Vo2+2gh
    Vt2=0 + 2.10.10
    Vt2=200
    Vt=√200

    4. dik : m=2ton = 2000kg
    h=5meter
    t=10detik
    g=10m/s
    dit : p?
    jwb : p=w/t
    p=m.g.h
    2000.10.5/10
    =10.ooo watt

    BalasHapus
  9. AnonimSel Mar 19, 11:53:00 AM 2013

    Fadilla Augustina
    X

    1. Dik : m= 50kg h=20m g=10m/s2
    dit : w
    jwb : W = m.g.h
    w=50.10.20=10.000 joule

    2.dik: F : 40 N sudut = 60 s = 10
    jwb : W =ΣF. s
    =F.sin60.s
    =40 1/2√3. 10
    =200√3 Joule

    3. Dik : m=2kg, h=10m, g=1om/s
    jwb : a. ep=m.g.h= 2.10.10 =200 joule
    b. em= m.g.h+ 1/2 m.v2
    = 2.10.10+1/2 2.02
    =200+1.0
    =200
    c) Ema = Emb
    Epa+Eka = Epb+Ekb
    mgha + 0= 0+ 1/2mv2
    mgha = 1/2 mvb2
    1/2vb2= gha
    vb2= gha/1/2
    vb= √2.10.10
    vb= 10 √2 m/s
    d. ketinggian 2m diatas tanah
    ep=m.g.h=2.2.10=40 joule
    e.ketinggian 2m diatas tanah
    ek=1/2 m.v2 = 1/2 2.02=0
    f.Vt2=Vo2+2gh
    Vt2=0 + 2.10.10
    Vt2=200
    Vt=√200

    4.dik : m=2ton=2000kg, h=5m, t=10s,g=10
    dit: daya
    jwb : P: W/t= m.g.h/t= 2000.10.5/10= 10.000 joule

    BalasHapus
  10. AnonimSel Mar 19, 11:53:00 AM 2013

    santika aulia kurnia X
    jawaban :
    1. Dik : m= 50kg h=20m g=10m/s2
    dit : w
    jwb : W = m.g.h
    w=50.10.20=10.000 joule

    2.dik: F : 40 N sudut = 60 s = 10
    jwb : W =ΣF. s
    =F.cos 60.s
    =40 .1/2. 10
    =200Joule

    3. Dik : m=2kg, h=10m, g=1om/s
    jwb : a. ep=m.g.h= 2.10.10 =200 joule
    b. em= m.g.h+ 1/2 m.v2
    = 2.10.10+1/2 2.02
    =200+1.0
    =200
    c. Ema = Emb
    Epa+Eka = Epb+Ekb
    mgha + 0= 0+ 1/2mv2
    mgha = 1/2 mvb2
    1/2vb2= gha
    vb2= gha/1/2
    vb= akar 2.10.10
    vb= 10 akar 2 m/s
    d. ketinggian 2m diatas tanah
    =m.g.h=2.2.10=40 joule
    e.ketinggian 2m diatas tanah
    ek=1/2 m.v2 = 1/2 2.02=0
    f.Vt2=Vo2+2gh
    Vt2=0 + 2.10.10
    Vt2=200

    4.dik : m=2 ton=2000kg, h=5m, t=10s,g=10
    dit: daya
    jwb : P: W/t= m.g.h/t= 2000.10.5/10= 10.000 joule
    Vt=√200

    BalasHapus
  11. AnonimSel Mar 19, 11:53:00 AM 2013

    Yune Rizdiani
    1)Dik : m= 50 kg
    h= 20 meter
    g= 10 m/s2
    Dit : w ?
    jawab : w= m.g.h
    = 50.20.10
    = 10.000 joule

    4)Dik : massa= 2 ton = 2000 kg
    h= 5 meter
    t= 10 detik
    g= 10 m/s2
    Dit : p ?
    jawab : p= w/t
    p= m.g.h/t
    = 2000.10.5/10
    = 10.000 watt

    2)Dik : F= 40 N
    sudut = 60
    s = 10
    Dit : w ?
    jawab : w =ΣF. s
    =F.cos 60.s
    =40 .1/2. 10
    =200Joule

    3)Dik : m= 2 kg
    h= 10 meter
    g= 10m/s2
    Dit : a) Ep ?
    b) Em ?
    c) v ?
    d) Ep ? h=2 meter di atas tanah
    e) Ek ? h=2 meter di atas tanah
    f) v sesaat menyentuh tanah ?
    Jawab : a)Ep=m.g.h
    =2.10.10 =200 joule

    b)Em= m.g.h+ 1/2 m.v2
    = 2.10.10+1/2 2.02
    =200+1.0
    =200 joule

    d)Ketinggian 2m diatas tanah
    Ep=m.g.h
    =2.2.10=40 joule

    c)Ema = Emb
    Epa+Eka = Epb+Ekb
    mgha + 0= 0+ 1/2mv2
    mgha = 1/2 mvb2
    1/2vb2= gha
    vb2= gha/1/2
    vb= akar 2.10.10
    vb= 10 akar 2 m/s

    e)Ketinggian 2m diatas tanah
    Ek=1/2 m.v2
    =1/2 2.02=0

    f)Vt2=Vo2+2gh
    Vt2=0 + 2.10.10
    Vt2=200
    Vt=√200

    BalasHapus
  12. AnonimSel Mar 19, 11:54:00 AM 2013

    1.Dik : m = 50kg h=20m g=10m/s2
    dit : w ?
    jawab : W = m.g.h
    w = 50.10.20=10.000 joule

    4. dik : m = 2ton (2.000 kg)
    h = 5 m
    t = 10 s
    g = 10 m/s2
    dit : p ?
    penyelesaian : p = w/t
    = mgh/t
    = 2.000.10.5/10
    = 2.000 . 5
    = 10.000 watt

    2 jawab = W = ΣF . s
    = F . Sin 60 . s
    = 40 1/2√3 . 10
    = 200√3 Joule

    3.dik : m =2kg h =10m g =10m/s
    jawab :
    (a)ep=m.g.h =2.10.10 =200 joule
    (b).em = m.g.h + m.v2 = 2.10.10 + 1/2 2.02 =200+1.0 = 200
    (d) ketinggian 2m diatas tanah
    ep = m.g.h=2.2.10=40 joule
    (e)ketinggian 2m diatas tanah
    ek=1/2 m.v2 = 1/2 2.02 = 0
    (c) Ema = Emb
    Epa + Eka = Epb + Ekb
    mgha + 0 = 0 + 1/2mv2
    mgha = 1/2 mvb2
    1/2vb2= gha
    vb2= gha/1/2
    vb= akar 2.10.10
    vb= 10 akar 2 m/s
    (f) Vt2 = Vo2+2gh
    Vt2= 0 + 2.10.10
    Vt2= 200
    Vt= √200



    BalasHapus
  13. AnonimSel Mar 19, 11:55:00 AM 2013

    yulinda nuraeni x
    jawaban :
    1.dik : m= 50kg
    h=20m
    g=10m/s
    dit : w ?
    jawab : w=m.g.h
    w=50.20.10
    w=10.000joule

    2 jawab =.W =ΣF. s
    =F.Sin 60.s
    =40 1/2√3. 10
    =200√3 Joule

    3.dik : m=2kg h=10m g=10m/s
    jawab :: a.ep=m.g.h =2.10.10 =200 joule
    b.em=m.g.h +m.v2 = 2.10.10 + 1/2 2.02 =200+1.0 = 200
    c) Ema = Emb
    Epa+Eka = Epb+Ekb
    mgha + 0= 0+ 1/2mv2
    mgha = 1/2 mvb2
    1/2vb2= gha
    vb2= gha/1/2
    vb= akar 2.10.10
    vb= 10 akar 2 m/
    d. ketinggian 2m diatas tanah
    ep=m.g.h=2.2.10=40 joule e.ketinggian 2m diatas tanah
    ek=1/2 m.v2 = 1/2 2.02=0
    f) Vt2=Vo2+2gh
    Vt2=0 + 2.10.10
    Vt2=200
    Vt=√200

    4.dik : m=2 ton=2000kg, h=5m, t=10s,g=10
    dit: daya
    jwb : P: W/t= m.g.h/t= 2000.10.5/10= 10.000 joule g.h =2.10.10 =200 joule
    b.em=m.g.h +m.v2 = 2.10.10 + 1/2 2.02 =200+1.0 = 200

    BalasHapus
  14. nenden yuliantiSel Mar 19, 11:56:00 AM 2013

    1.Dik =m =50 kg
    =g =10 m/s2
    =h =20 m
    Dit=w ?
    jawab =
    W=m.g.h
    W=50kg.10m/s2.20m
    W=10000 joule

    2.Dik =F=40 N
    Sin 60(derajat)=1/2 akar 3
    S=10 m
    Dit =w ?
    jawab=sigmaf.s
    =sin 60(derajat).f.s
    =1/2akar3.40 N.10m
    =1/2akar3.400 N/m
    =200akar3

    3.Dik =m=2 kg
    h=10 m
    g=10m/s2
    a.Epot =m.g.h
    =2kg.10m/s2.10m
    =200 J
    b.Eme=Epo+Eki
    =200 J + 0
    =200 J
    C.Ema= Emb
    Epa+Eka=Epb+Ekb
    mgha + 0= 0+ 1/2mv2
    mgha = 1/2 mvb2
    1/2vb2= gha
    vb2= gha/1/2
    vb= akar 2.10.10
    vb= 10 akar 2 m/s
    D.Epot =m.g(h2-h1)
    =2kg.10m/s2(10-2)
    =2kg.10m/s2(8)
    =160 J
    E.Ekin=m.1/2.v2
    =2.1/2.0.2
    =0 J
    F.VT2=VO2+2g.h
    =0+2.10.50
    =200
    vt=akar 200
    vt=10akar2

    4.Dik =m=2 ton=2000 kg
    h=5 m
    g=10 m/s2
    t=10 s
    Dit=p?
    jawab=
    p=m.g.h/t
    p=2000 kg.10 m/s2.5m/10s
    p=10000 watt/s

    BalasHapus
  15. AnonimSel Mar 19, 11:56:00 AM 2013

    shanti sulastri
    x
    1.dik : m= 50kg
    h=20m
    g=10m/s
    dit : w ?
    jawab : w=m.g.h
    w=50.20.10
    w=10.000joule

    2 jawab =.W =ΣF. s
    =F.Sin 60.s
    =40 1/2√3. 10
    =200√3 Joule

    3.dik : m=2kg h=10m g=10m/s
    jawab : a.ep=m.g.h =2.10.10 =200 joule
    b.em=m.g.h +m.v2 = 2.10.10 + 1/2 2.02 =200+1.0 = 200
    c) Ema = Emb
    Epa+Eka = Epb+Ekb
    mgha + 0= 0+ 1/2mv2
    mgha = 1/2 mvb2
    1/2vb2= gha
    vb2= gha/1/2
    vb= akar 2.10.10
    vb= 10 akar 2 m/s
    d. ketinggian 2m diatas tanah
    ep=m.g.h=2.2.10=40 joule
    e.ketinggian 2m diatas tanah
    ek=1/2 m.v2 = 1/2 2.02=0
    f. Vt2=Vo2+2gh
    Vt2=0 + 2.10.10
    Vt2=200
    Vt=√200

    4.dik : m=2 ton=2000kg, h=5m, t=10s,g=10
    dit: daya
    jwb : P: W/t= m.g.h/t= 2000.10.5/10= 10.000 joule

    BalasHapus
  16. Salma SaidahSel Mar 19, 11:56:00 AM 2013

    Komentar ini telah dihapus oleh pengarang.

    BalasHapus
  17. destiani nuraini hasnaSel Mar 19, 11:56:00 AM 2013

    1. dik : m = 50 kg
    h = 20 m
    g = 10 m/s2
    dit : W ?
    jawab : w = m.g.h
    = 50 kg.10 m/s2.20 m
    = 10000 joule
    2. dik : f = 40 N
    sin 60(derajat)= 1/2 akar 3
    s : 10 m
    dit : w ?
    jawab : w = sigmaF.s
    = 1/2 akar 3.40 N.10 m
    = 1/2 akar 3.400 N/m
    = 200 akar 3
    3. dik : m = 2 kg
    h = 10 m
    g = 10 m/s2
    dit : Epot ?
    jawab : a. Epot = m.g.h
    = 2kg.10m/s2.10m
    = 200 joule
    b. EmA = EpA + EkA
    = 200 j + 1/2 m.v2
    = 200 j + 1/2 2.0
    = 200 joule
    c. V = Ema = Emb
    Epa+Eka = Epb+Ekb
    mgha + 0= 0+ 1/2mv2
    mgha = 1/2 mvb2
    1/2vb2 = gha
    vb2 = gha/1/2
    vb = akar 2.10.10
    vb = 10 akar 2 m/s
    d. Epot = m.g.(h2-h1)
    = 2.10(10-2)
    = 160 joule
    e. Ekin = =m.1/2.v2
    =2.1/2.0.2
    =0 J
    f. = Vt2-Vo2 + 2.g.h
    = 0+2.10.50
    = 200
    Vt2 = akar 200
    Vt = 10 akar2
    4. Dik : m =2 ton = 2000 kg
    h = 5 m
    g = 10 m/s2
    t = 10 joule
    Dit : p?
    jawab :p =w/t
    =m.g.h/t
    =2000kg.10m/s2.5m/10 s
    =100000/10
    =10000 watt

    BalasHapus
  18. intan nuranggraeniSel Mar 19, 12:04:00 PM 2013

    1. Dik : m= 50kg h=20m g=10m/s2
    dit : w
    jwb : W = m.g.h
    w=50.10.20=10.000 joule

    2.dik: F : 40 N sudut = 60 s = 10
    jwb : W =ΣF. s
    =F.sin60.s
    =40 1/2√3. 10
    =200√3 Joule

    3. Dik : m=2kg, h=10m, g=1om/s
    jwb :
    a) ep=m.g.h= 2.10.10 =200 joule

    b) em= m.g.h+ 1/2 m.v2
    = 2.10.10+1/2 2.02
    =200+1.0
    =200

    c) Ema = Emb
    Epa+Eka = Epb+Ekb
    mgha + 0= 0+ 1/2mv2
    mgha = 1/2 mvb2
    1/2vb2= gha
    vb2= gha/1/2
    vb= √2.10.10
    vb= 10 √2 m/s

    d)ketinggian 2m diatas tanah
    ep=m.g.h=2.2.10=40 joule
    e.ketinggian 2m diatas tanah
    ek=1/2 m.v2 = 1/2 2.02=0

    f) Vt2=Vo2+2gh
    Vt2=0 + 2.10.10
    Vt2=200
    Vt=√200

    4.dik : m=2ton=2000kg, h=5m, t=10s,g=10
    dit: daya
    jwb : P: W/t= m.g.h/t= 2000.10.5/10= 10.000 joule

    BalasHapus
  19. reski sanusiSel Mar 19, 12:10:00 PM 2013

    fisika

    1. Dik : m= 50kg h=20m g=10m/s2
    dit : w
    jwb : W = m.g.h
    w=50.10.20=10.000 joule

    2.dik: F : 40 N sudut = 60 s = 10
    jwb : W =ΣF. s
    =F.sin60.s
    =40 1/2√3. 10
    =200√3 Joule

    3. Dik : m=2kg, h=10m, g=1om/s
    jwb : a. ep=m.g.h= 2.10.10 =200 joule
    b. em= m.g.h+ 1/2 m.v2
    = 2.10.10+1/2 2.02
    =200+1.0
    =200
    c) Ema = Emb
    Epa+Eka = Epb+Ekb
    mgha + 0= 0+ 1/2mv2
    mgha = 1/2 mvb2
    1/2vb2= gha
    vb2= gha/1/2
    vb= √2.10.10
    vb= 10 √2 m/s
    d. ketinggian 2m diatas tanah
    ep=m.g.h=2.2.10=40 joule
    e.ketinggian 2m diatas tanah
    ek=1/2 m.v2 = 1/2 2.02=0
    f.Vt2=Vo2+2gh
    Vt2=0 + 2.10.10
    Vt2=200
    Vt=√200

    4.dik : m=2ton=2000kg, h=5m, t=10s,g=10
    dit: daya
    jwb : P: W/t= m.g.h/t= 2000.10.5/10= 10.000 joule

    BalasHapus
  20. AnonimSel Mar 19, 12:11:00 PM 2013

    1.m=50kg
    h=20m
    g=10m/s
    w=?
    jawab;w=m.g.h
    =50.20.10
    =10000
    2.f=40n
    s=10m
    w=/
    jawab;w=zf.s
    =40.cos 60.10
    =40.1/2.10
    =20.10
    =200
    3. Dik : m=2kg,
    h=10m,
    g=1om/s
    jwb : a. ep=m.g.h
    = 2.10.10
    =200 joule
    b. em= m.g.h+ 1/2 m.v2
    = 2.10.10+1/2 2.02
    =200+1.0
    =200
    c) Ema = Emb
    Epa+Eka = Epb+Ekb
    mgha + 0= 0+ 1/2mv2
    mgha = 1/2 mvb2
    1/2vb2= gha
    vb2= gha/1/2
    vb= akar 2.10.10
    vb= 10 akar 2 m/s
    d. ketinggian 2m diatas tanah
    ep=m.g.h
    =2.2.10
    =40 joule
    e)ketinggian 2m diatas tanah
    ek=1/2 m.v2 = 1/2 2.02=0
    f) Vt2=Vo2+2gh
    Vt2=0 + 2.10.10
    Vt2=200
    Vt=√200
    4. dik : m=2ton=2000kg, h=5m, t=10s,g=10
    dit: daya
    jwb : P: W/t= m.g.h/t
    = 2000.10.5/10
    = 10.000 joule

    BalasHapus
  21. tauhid iksanSel Mar 19, 12:14:00 PM 2013

    1. Dik : m= 50kg h=20m g=10m/s2
    dit : w
    jwb : W = m.g.h
    w=50.10.20=10.000 joule
    2.dik: F : 40 N sudut = 60 s = 10
    jwb : W =ΣF. s
    =F.cos 60.s
    =40 .1/2. 10
    =200Joule
    3. Dik : m=2kg, h=10m, g=1om/s
    jwb :
    A). ep=m.g.h= 2.10.10 =200 joule
    . em= m.g.h+ 1/2 m.v2
    = 2.10.10+1/2 2.02
    =200+1.0
    =200
    c) Ema = Emb
    Epa+Eka = Epb+Ekb
    mgha + 0= 0+ 1/2mv2
    mgha = 1/2 mvb2
    1/2vb2= gha
    vb2= gha/1/2
    vb= akar 2.10.10
    vb= 10 akar 2 m/s
    D). ketinggian 2m diatas tanah
    ep=m.g.h=2.2.10=40 joule
    E).ketinggian 2m diatas tanah
    ek=1/2 m.v2 = 1/2 2.02=0
    F) Vt2=Vo2+2gh
    Vt2=0 + 2.10.10
    Vt2=200
    Vt=√200
    4.dik : m=2 ton=2000kg, h=5m, t=10s,g=10
    dit: daya
    jwb : P: W/t= m.g.h/t= 2000.10.5/10= 10.000 joule

    BalasHapus
  22. furqon aminudinSel Mar 19, 12:16:00 PM 2013

    1. Dik : m= 50kg h=20m g=10m/s2
    dit : w
    jwb : W = m.g.h
    w=50.10.20=10.000 joule

    2.dik: F : 40 N sudut = 60 s = 10
    jwb : W =ΣF. s
    =F.sin60.s
    =40 1/2√3. 10
    =200√3 Joule

    3. Dik : m=2kg, h=10m, g=1om/s
    jwb : a. ep=m.g.h= 2.10.10 =200 joule
    b. em= m.g.h+ 1/2 m.v2
    = 2.10.10+1/2 2.02
    =200+1.0
    =200
    c) Ema = Emb
    Epa+Eka = Epb+Ekb
    mgha + 0= 0+ 1/2mv2
    mgha = 1/2 mvb2
    1/2vb2= gha
    vb2= gha/1/2
    vb= √2.10.10
    vb= 10 √2 m/s
    d. ketinggian 2m diatas tanah
    ep=m.g.h=2.2.10=40 joule
    e.ketinggian 2m diatas tanah
    ek=1/2 m.v2 = 1/2 2.02=0
    f.Vt2=Vo2+2gh
    Vt2=0 + 2.10.10
    Vt2=200
    Vt=√200

    4.dik : m=2ton=2000kg, h=5m, t=10s,g=10
    dit: daya
    jwb : P: W/t= m.g.h/t= 2000.10.5/10= 10.000 joule

    BalasHapus
  23. aji setiaSel Mar 19, 12:16:00 PM 2013

    1. Dik : m= 50kg h=20m g=10m/s2
    dit : w
    jwb : W = m.g.h
    w=50.10.20=10.000 joule
    2.dik: F : 40 N sudut = 60 s = 10
    jwb : W =ΣF. s
    =F.cos 60.s
    =40 .1/2. 10
    =200Joule
    3. Dik : m=2kg, h=10m, g=1om/s
    jwb :
    A). ep=m.g.h= 2.10.10 =200 joule
    . em= m.g.h+ 1/2 m.v2
    = 2.10.10+1/2 2.02
    =200+1.0
    =200
    c) Ema = Emb
    Epa+Eka = Epb+Ekb
    mgha + 0= 0+ 1/2mv2
    mgha = 1/2 mvb2
    1/2vb2= gha
    vb2= gha/1/2
    vb= akar 2.10.10
    vb= 10 akar 2 m/s
    D). ketinggian 2m diatas tanah
    ep=m.g.h=2.2.10=40 joule
    E).ketinggian 2m diatas tanah
    ek=1/2 m.v2 = 1/2 2.02=0
    F) Vt2=Vo2+2gh
    Vt2=0 + 2.10.10
    Vt2=200
    Vt=√200
    4.dik : m=2 ton=2000kg, h=5m, t=10s,g=10
    dit: daya
    jwb : P: W/t= m.g.h/t= 2000.10.5/10= 10.000 joule

    BalasHapus
  24. Rivia Alma AzharaSel Mar 19, 12:49:00 PM 2013

    nama : rifka khoioerunnisa
    kelas : x
    sekolah : SMK CHEMICA

    1. dik: M=50kg h=20m g=10m/s2
    dit: W
    jawab: w= m.g.h
    w=50.10.20
    w=10.000 joule

    3. dik: m=2kg h=10m g=10m/s2
    dit& jawab: a. e.potensial
    w=m.g.h
    w=2.10.10
    w=200 joule
    b.e.mekanik
    e.kin= 1/2.m.v2
    v2=g.h/ 1/2
    v2= 2 gh
    v=√2.10.10
    v=√200
    v=2√5m/s

    e.kin=1/2.10.200
    e.kin=1000 joule

    em=e.pot+e.kin
    em=200+1000
    em=1200 joule

    d. e.pot dalam h=2m
    e.pot=m.g.h
    e.pot=2.10.2
    e.pot=40 joule

    e. e.kin dalam h=2m
    e.kin= 1/2.m.v2
    e.kin=1/2.2.200
    e.kin=200 joule

    4. dik: m=2ton=2000kg h=5m g=10 m/s2 t=10s
    dit:P
    jawab: p=W/T

    w=m.g.h
    w=2000.5.10
    w=100000 joule

    p=100000/10
    p=10000 joule

    2.dik: f=40N cos 60o s=10m
    dit:usaha
    jawab; w= 40. 10. o,3. 1/2
    w= 60 joule

    BalasHapus
  25. Fitri VetiSel Mar 19, 01:19:00 PM 2013

    Nama : Firi Veti F
    Kelas ; epuluh
    SMK Chemica

    1. Dik ; m= 50kg, h= 20m, g= 10m/s2
    Dit : W ?
    Jawab : W= m.g.h
    W= 50.10.20
    W= 10000 Joule

    2.Dik: F : 40 N sudut = 60 s = 10
    Dit :W ?
    Jawab : W =ΣF. s
    =F.Sin 60.s
    =40 .1/2 √3. 10
    =20. 1,7 .10
    = 34.10
    = 340 Joule
    3. Dik : m=2 kg, h=10m, g=10m/s2
    Dit : a) Energi potensial benda pada ketinggian tersebut
    b) Energi mekanik pada ketinggian tersebut
    c) Kecepatan benda pada ketinggian tersebut
    d) Energi potensial benda pada ketinggian 2 meter diatas tanah
    e) Energi kinetik benda pada ketinggian 2 meter diatas tanah
    f) Kecepatan benda sesaat menyentuh tanah

    Jawab : A. E.P =m.g.h
    = 2.10.10
    =200 joule
    B. E.M = m.g.h +1/2.m.V2
    =2.10.10 +1/2.2.10 √2 (2)
    =200 + 1/2.2.100 √2
    =200 + 1/2.200. 1.4
    =200 + 100.1,4
    = 200 + 140
    = 340 Joule
    V 100 dari Vt2= 2g.h
    Vt2= 2.10.10
    Vt2 = 200
    Vt= 10 √2
    C. Ema = Emb
    Epa+= Epb+Ekb
    m.g.ha + 0Eka = 0+ 1/2.m.V2
    m.g.ha = 1/2 m.Vb2
    1/2.Vb2 = g.h.a
    Vb2 = g.ha/1/2
    Vb = √2.10.10
    Vb = 10 √2 m/s

    D. m=2 kg, h=10-2=8m, g=10m/s2
    E.P = m.g.h
    = 2.10.8
    = 160 Joule

    E. Vt2=2 g.h
    = 2. 10.8
    Vt2 = 160
    Vt = 80√2
    E.K = 1/2.m.V2
    =1/2.2. 80√2
    = 1/2.160 √2
    = 80. 1,4
    = 112
    F. Vt2=Vo2+2gh
    Vt2=0 + 2.10.10
    Vt2=200
    Vt=√200

    4. Dik : m=2 ton (2000 kg), h=5m, t=10s,g= 10 m/s2
    Dit : P ?
    Jawab : P= W/t
    P = m.g.h/t
    P = 2000.10.5/10
    P = 100000/10
    P = 10000 watt

    BalasHapus

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